Now we will check if the year is divisible by 4 but not by 100 then there will be "leap year". A year can be checked whether a year is leap year or not by dividing the year by 4, 100 and 400. One year has the length of 365 days, 5 hours, 48 minutes and 45 seconds.This is hard to calculate with, so a normal year has been given 365 days and a leap year 366 days.In leap years, February 29th is added as leap day, which doesn’t exist in a normal year. In this program below, user is asked to enter a year and this program checks whether the year entered by user is leap year or not. Find leap year or not, using nested if-else #include #include void main() {int year; clrscr(); The following is a C program which checks whether the entered year is a leap year or not. Print all Leap Years from 1 to N using C program A year is called leap year if the year is divisible by four, except for the years which are divisible by 100 but not divisible by 400. Also Read: C Program To Delete Vowels From A String The program that checks if a year is leap year or not is as follows − Example. (year%100 != 0 && year%4 == 0) Expected Output for the Input. 3. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20… Example: A year is said to be a leap year if it is divisible by 4. Year that is divisible by 4 but not divisible by 100. If a year is divisible by 4 without generating any remainder, the year is a leap year. C Program to Find if a given Year is a Leap Year. Home c program write a c program to find leap year or not, using nested if-else write a c program to find leap year or not, using nested if-else Hanif Miah January 05, 2019. C Program to Check Year is a Leap Year or Not. C program to check leap year in one year there are 365.25 days. A centurial year will be a leap year if it is exactly divisible by 400, for example, the year 1700 is not a leap year whereas 2000 is a leap year. Here's what I've done: We know that there are 365 day in a year but it is wrong. year) Enter the year to check if it is a leap year or not; Divide the year by 400. The first If condition will check whether the (year % … Note: This Code to Find Leap Year in C Programming has been compiled with GNU GCC Compiler and developed with gEdit Editor and Terminal in Linux Ubuntu Operating System. We can use if-else, nested if-else, or switch case statement for this problem. We also know that 01 January 1900 was Monday. Leap year is calendar year having one extra day which is to make a synchronized and seasonal year. Using this mathematical argument In the leap year program in C you can check if there is a leap year: Year: Divide a year by 4, 100, and 400, and it’s a leap year If a year is divided by 4 but not divisible by 100, it is a leap year. Leap Year Program: A leap year has 366 days whereas a non-leap year has 365 days. In this C Program to Check Leap Year example, the user will enter any year to check whether that year is Leap year or Not. If a number is divisible by 4 but not by 100 then, it is a leap year. Example 1: Input: N = 4 Output: 1 Explanation: 4 is not divisible by 100 and is divisible by 4 so its a leap year Example 2: Input: N = 2021 Output: 0 Explanation: 2021 is not divisible by 100 and is also not divisible by 4 so its not a leap year Your Task: You don't need to read input or print anything. C Program to check whether a given year is leap year or not.Write a program to check leap year. Therefore, the year 2000 was a leap year, but the years 1700, 1800, and 1900 were not. With this we come to the end of this blog on ‘Leap Year Program In C’. Example. A leap year contains one additional day that is added to keep the calendar year synchronized with the astronomical year. Leap year has one additional day that is added to the calendar. If a year is exactly divisible by 4 and not divisible by 100 then its Leap year. A year is called leap year if the year is divisible by four, except for the years which are divisible by 100 but not divisible by 400. Not a Leap Year: If a year is not divided by 4 classes, it is not a leap year User Input: Enter a year 2024. (year%100 == 0 && year%400 == 0) If the year is not century year, then it must be perfectly divisible by 4, for the year to be a leap year. This is exactly what is done in the conditional statements above. In this post, we will write a leap year program in the C++ language. This C# Program Checks Whether the Entered Year is a Leap Year or Not. Output: 2024 is a leap year. These are the 4 conditions to check for to check whether if it is a leap year or no. C Programming & Data Structures: C Program to check if the given year is a leap year or not. If any year is input through the keyboard write a program to find out what is the day on 1st January of this year. Leap year program in C. This program takes a year as input and finds whether a year is the leap year or not. This Leap Year C Program is based on the Gregorian Calendar. Leap year condition. Last, if it is not divisible by 4,400 or 100 it isn’t a leap year. In this article, you will learn the concept of C program to check leap year i.e. A year that has 366 days is called a leap year. A year that is divisible by 4 is known as a leap year. This program will read value of N and print all Leap Years from 1 to N years.There are two conditions for leap year: 1-If year is divisible by 400 ( for Century years), 2-If year is divisible by 4 and must not be divisible by 100 (for Non Century years). Basic C programming, Conditional operator, Logical operators. For example, 2021, 2018, 2019,2022,2015 etc. Learn more - Program to check leap year using if...else Leap year condition. Very common question asked in various academic level exams. But it is not the only case. Else its a Common year. 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